How to find the angle here?

Can the angle be obtained using just this information? Also, wouldn’t that be nice?

Of course it can :wink:

Assume you cut this triangle in half, exactly on the line from the corner you marked with ? and the center of C. Then you have a right-angled triangle.

C/2 = A * sin(phi/2)
C / (2A) = sin(phi/2)
phi = 2 * arcsin(C / (2

That did it, thanks!

Do a google search on the following … you will find lots of formulas for computing similar stuff. Your application in particular is SSS

Law of Cosines