I need to get the inverse matrix of the model-view matrix.
To do it faster can I do it in the following way:
1- Multiply by (-1) the translation vector in the matrix (only X, Y, Z items of the vector)
2- Calculate the transpose of the 3x3 sub matrix that contains the rotation vectors
3- Update the first three items of the diagonal with this 1/m11, 1/m22, 1/m33
Of course that method is only valid for the following transformations:
Can I calculate the inverse in that way? I mean, is this an accurate way to get the inverse?
PD: I will only do these transformations in the model-view.