An Axis Aligned Bounding Box (min, max coordinates)

A Ray entry point in this Box (Pin)

The normalized ray direction vector (Rd)
Is there a way to determine the coordinates of the exit point Pout without having to test each plane of the box?
The coordinates are given in 3D.
Illustration in 2D:

__Pout_____ max
| / |
| / |
|/ |
Pin |
|___________|
min

I’ve decided to implement the whole AABB vs Ray test, which can be simplified in my scenario. Here’s the code in GLSL, if it can help others

struct Ray
{
vec3 o; // ray origin
vec3 d; // ray direction unit vector
};
struct Box
{
vec3 m[2]; // min and max
};
// compute exit point of ray from a AABB
vec3 ray_box_exit(in Ray r, in Box b)
{
vec3 tmax;
vec3 div = 1.0 / r.d;
ivec3 indexes = ivec3(step(0.0,div));
tmax.x = (b.m[indexes[0]].x - r.o.x) * div.x;
tmax.y = (b.m[indexes[1]].y - r.o.y) * div.y;
tmax.z = (b.m[indexes[2]].z - r.o.z) * div.z;
return r.o + min(min(tmax.x, tmax.y), tmax.z) * r.d;
}